// 쑰쀀탄

double ν”Œλ ˆμ΄μ–΄μ’Œν‘œ(x,y)

double νƒ„λ§‰μƒμ„±ν• μ’Œν‘œ(gx, gy)

double νƒ„λ§‰μ’Œν‘œ(bx, by)



μƒμ„±μž {

bx = gx; by = gy;


d = √((x-gx)^2+(y-gy)^2));

vx = (x-gx)*(속도)/d;

vy = (x-gy)*(속도)/d;

//단, (x,y)=(bx,by)인 κ²½μš°μ—λŠ” μƒμ„±ν•˜μ§€ μ•ŠμŒ

}


μ‘°μ€€νƒ„μ΄λ™ν•¨μˆ˜{

bx += vx;

by += vy;

}


질문 1. μ΄λ ‡κ²Œ ν–ˆλŠ”λ°, νŠΉμ • κ°λ„μ—μ„œλŠ” λ―Έλ¬˜ν•˜κ²Œ 탄막 λ‚ μ•„κ°€λŠ” 속도가 λ‹¬λΌμ§€λŠ” 것 κ°™μŒ.Β 

Β λ‚΄κ°€ 이걸 κ΅¬ν˜„ν•˜λ €λŠ” ν™˜κ²½μ—μ„œλŠ” μ’Œν‘œλ₯Ό μ†Œμˆ˜μ  μ•„λž˜λ₯Ό κ΅¬ν˜„ν•˜μ§€ μ•Šμ•„μ„œ, bx,byλŠ” κΉŒμ§€λŠ” 더블값인데, 이후 화면에 κ·Έλ¦¬λŠ” λΆ€λΆ„μ—μ„œλŠ”Β κ³ μ •μ†Œμˆ˜μ  κ³„μ‚°μœΌλ‘œ λ•Œμ› μŒ. 이것 λ•Œλ¬Έμ΄λ €λ‚˜?Β 


질문 2. λ§Œμ•½μ— μœ„ 방법 말고 DDA둜 κ΅¬ν˜„ν•˜λ©΄ λ‚ μ•„κ°€λŠ” λ°©ν–₯은 μ’€ μ°Œκ·ΈλŸ¬λ“€λ”λΌλ„ μ†λ„λŠ” κ°™μœΌλ €λ‚˜?Β