viewimage.php?id=2abcdd23dad63db0&no=24b0d769e1d32ca73ced8ffa11d02831dfaf0852456fb219302713c4cd87ae384bec2ab5f390c3dff051e7a59928736d4d2673f94c15e77fe3dc3b8b21e4261e621ee9


viewimage.php?id=2abcdd23dad63db0&no=24b0d769e1d32ca73ced8ffa11d02831dfaf0852456fb219302713c4cd87ae384bec2ab5f390c3dff051e7a59928736d4d2673f94c15e773b3d8368c24e5271e533b7b


λ ˆμ΄μ•„μ›ƒ λ¨Ήμ—¬λ†¨λŠ”λ° μ”¬μ΄λž‘ κ²Œμž„μ΄λž‘ μ €λ ‡κ²Œ μ°¨μ΄λ‚˜μ„œ 2μ‹œκ°„ λ™μ•ˆ λΆ™μž‘κ³  μžˆμ—ˆλŠ”λ°λ„ 해결을 λͺ»ν•˜κ² λ‹€ γ……γ…‚..


그리고 λ ˆμ΄μ•„μ›ƒ κΈ°λŠ₯ 쀑에 use child scale은 μ™œμžˆλŠ”κ±°μž„? 이거 μ“°λ©΄ μ‹œλ°œ μžμ‹μƒˆλΌλ„ 같이 2배둜 λŠ˜μ–΄λ‚˜μ„œ κΉ¨μ§€λŠ”κ±° 암걸리넀