5차 이상 방정식 사칙연산과 근호 결합으로 (해답 정답 푸는방법설명)

[익명(61.83)]

(x+a)(x+b)(x+c)(x+d)(x+e) = x^5 + (a+b+c+d+e)x^4 + (ab+ac+ad+ae+bc+bd+be+cd+ce+de)x^3 + (abc+abd+abe+acd+ace+ade+bcd+bce+bde+cde)x^2 + (abcd+abce+abde+acde+bcde)x + abcde

(ex+a)(fx+b)(gx+c)(hx+d)(ix+e) = e.000000a *f.000000b *g.000000c*h.00000d * i.000000e

(1x+2)(2x+2)(3x+3)(2x+5)(1x+4) =

1.000002 * 2.000002*3.000003*2.000005*1.000004=12.00012600049200089400075600024

12.00012600049200089400075600024

12.(x^5)+

000126(x^4)+

000492(x^3)+

000894(x^2)+

000756(x)+

000240

= 12x^5+126x^4+492x^3+894x^2+756x+240