[❓️질문] 이거 극한값 어캐 계산함

[익명(w3v0cxm6j8lc)]

흠

[알락(1ll1ll111l)]

걍 a/2 아님뇨?

[익명(w3v0cxm6j8lc)]

맞음

[미분(paluchi)]

2n< x <=2(n+1)일때 f(x)=na + (3x+9)/(x+1) f(x)/2(n+1) <=f(x)/x < f(x)/2n x ->∞ n -> ∞하면 a/2

[익명(w3v0cxm6j8lc)]

ㄱㅅㄱㅅ