Target Regex: (100+1+|01)+

https://www.acmicpc.net/problem/1013


1. Regex to NFA (using mcnaughotn yamada thomspson construction algorithm)


2. e-clousre NFA to simplify dfa traslation


3. NFA to DFA using stacking


4. Optimize(Minimization) DFA




이제 이걸 그대로 코드로 옮기면

Answer:

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#include <iostream>
 
using namespace std;
 
int dfa[2][9= {
    2,3,-1,5,2,5,2,8,5,
    1,-1,4,-1,1,6,7,7,4
};
 
int main()
{
    int t;
    cin >> t;
    
    while ( t-- )
    {
        char s[201];
        cin >> s;
 
        int f = 0;
        for (int i = 0; s[i]; i++)
            if ((f = dfa[s[i] - '0'][f]) == -1)
                break;
 
        if (f == 4 || f == 6 || f == 7)
            cout << "YES" << endl;
        else cout << "NO" << endl;
    }
 
    return 0;
}
cs



ㅇㅇ