굉장히 쉬운 로직인데 이거 예외 케이스가 있나? 계속 틀렸다고 뜨네

[익명(223.194)]

#include<iostream>

using namespace std;

class Time {

public:

    int H, M, S;

    Time(int h, int m, int s) {

        //todo : Implement constructor

        this->H = h;

        this->M = m;

        this->S = s;

    }

    Time operator+(const Time& input) {

        //todo : Implement addition

        int s = input.S + this->S;

        int m = input.M + this->M + s / 60;

        int h = input.H + this->H + m / 60;

        s %= 60;

        m %= 60;

        h %= 24;

        return Time(h, m, s);

    }

    Time operator-(const Time& input) {

        //todo : Implement subtraction

        int s = this->S - input.S + 60;

        int m = this->M - input.M + s / 60 + 59;

        int h = this->H - input.H + m / 60 + 23;

        s %= 60;

        m %= 60;

        h %= 24;

        return Time(h, m, s);

    }

    Time operator*(const int& input) {

        //todo : Implement subtraction

        int s = input * this->S;

        int m = input * this->M + s / 60;

        int h = input * this->H + m / 60;

        s %= 60;

        m %= 60;

        h %= 24;

        return Time(h, m, s);

    }

    friend Time operator*(int& input, Time& p) {

        return p * input;

    }

    void print_time() {

        cout << H << ":" << M << ":" << S << endl;

    }

};

//todo : Implement time multiplication

int main() {

    int a, b, c;

    int d, e, f;

    int num1, num2;

    cin >> a >> b >> c;

    cin >> d >> e >> f;

    cin >> num1 >> num2;

    Time t1(a, b, c);

    Time t2(d, e, f);

    Time sum = t1 + t2;

    Time diff = t1 - t2;

    Time mul1 = t1 * num1;

    Time mul2 = num2 * t2;

    sum.print_time();

    diff.print_time();

    mul1.print_time();

    mul2.print_time();

    return 0;

}