A non-empty zero-indexed array A consisting of N integers is given. A pair of integers (P, Q), such that 0 ≤ P < Q < N, is called a slice of array A (notice that the slice contains at least two elements). The average of a slice (P, Q) is the sum of A[P] + A[P + 1] + ... + A[Q] divided by the length of the slice. To be precise, the average equals (A[P] + A[P + 1] + ... + A[Q]) / (Q − P + 1).

For example, array A such that:

A[0] = 4 A[1] = 2 A[2] = 2 A[3] = 5 A[4] = 1 A[5] = 5 A[6] = 8

contains the following example slices:

  • slice (1, 2), whose average is (2 + 2) / 2 = 2;
  • slice (3, 4), whose average is (5 + 1) / 2 = 3;
  • slice (1, 4), whose average is (2 + 2 + 5 + 1) / 4 = 2.5.


Complexity:

  • expected worst-case time complexity is O(N);
  • expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).

Elements of input arrays can be modified.


대충 이거 보면 적어도 시간복잡도 n^2 나오는거아니냐? 어떻게  N만에 워스트 케이스로 뽑아낼수 있지?