import java.math.BigInteger;
import java.util.function.LongToDoubleFunction;
/* The four adjacent digits in the 1000-digit number
* that have the greatest product are 9 × 9 × 8 × 9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number
that have the greatest product. What is the value of this product?
*/
public class Problem8 {
private static final String longDigit =
"73167176531330624919225119674426574742355349194934" +
"96983520312774506326239578318016984801869478851843" +
"85861560789112949495459501737958331952853208805511" +
"12540698747158523863050715693290963295227443043557" +
"66896648950445244523161731856403098711121722383113" +
"62229893423380308135336276614282806444486645238749" +
"30358907296290491560440772390713810515859307960866" +
"70172427121883998797908792274921901699720888093776" +
"65727333001053367881220235421809751254540594752243" +
"52584907711670556013604839586446706324415722155397" +
"53697817977846174064955149290862569321978468622482" +
"83972241375657056057490261407972968652414535100474" +
"82166370484403199890008895243450658541227588666881" +
"16427171479924442928230863465674813919123162824586" +
"17866458359124566529476545682848912883142607690042" +
"24219022671055626321111109370544217506941658960408" +
"07198403850962455444362981230987879927244284909188" +
"84580156166097919133875499200524063689912560717606" +
"05886116467109405077541002256983155200055935729725" +
"71636269561882670428252483600823257530420752963450";
private BigInteger adjacentProduct(int begin, int nAdjacent) {
char[] subArray = longDigit.substring(begin, begin+nAdjacent).toCharArray();
BigInteger product = new BigInteger("1");
for (char c : subArray) {
product = product.multiply(new BigInteger(String.valueOf(c)));
}
return product;
}
public BigInteger solve(int nAdjacent) {
BigInteger max = new BigInteger("0");
for (int begin=0; begin <= longDigit.length()-nAdjacent; begin++) {
BigInteger product = adjacentProduct(begin, nAdjacent);
if(product.compareTo(max) > 0) {
max = product;
}
}
return max;
}
public static void main(String[] args) {
//23514624000
System.out.println(new Problem8().solve(13));
}
}
인티져 max_value 범위가 넘어가서 빅인티져를 사용했는데 primitive 타입이 아니라 연산할때 불편하고 느리다.... 그냥 long 을 썼으면 더 좋았을듯
char 이 숫자일때 '0' 을 빼면 그 숫자인 int 가 나오는걸 이용해서 곱을 했으면 더 좋았을듯